Base | Representation |
---|---|
bin | 11101010000111001001… |
… | …011111101001111000001 |
3 | 21010020202100001120211101 |
4 | 131100321023331033001 |
5 | 230422014024131431 |
6 | 4135501553414401 |
7 | 265201362032311 |
oct | 35207113751701 |
9 | 7106670046741 |
10 | 2011004130241 |
11 | 70595344a7a7 |
12 | 2858b526a401 |
13 | 1178382a6942 |
14 | 6d494117441 |
15 | 3749e0d5961 |
hex | 1d4392fd3c1 |
2011004130241 has 2 divisors, whose sum is σ = 2011004130242. Its totient is φ = 2011004130240.
The previous prime is 2011004130181. The next prime is 2011004130269. The reversal of 2011004130241 is 1420314001102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1414919766016 + 596084364225 = 1189504^2 + 772065^2 .
It is a cyclic number.
It is not a de Polignac number, because 2011004130241 - 211 = 2011004128193 is a prime.
It is a super-2 number, since 2×20110041302412 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2011004130041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005502065120 + 1005502065121.
It is an arithmetic number, because the mean of its divisors is an integer number (1005502065121).
Almost surely, 22011004130241 is an apocalyptic number.
It is an amenable number.
2011004130241 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011004130241 is an equidigital number, since it uses as much as digits as its factorization.
2011004130241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 2011004130241 its reverse (1420314001102), we get a palindrome (3431318131343).
The spelling of 2011004130241 in words is "two trillion, eleven billion, four million, one hundred thirty thousand, two hundred forty-one".
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