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201101012153 is a prime number
BaseRepresentation
bin1011101101001010001…
…1011110110010111001
3201020002002000220020022
42323102203132302321
511243323324342103
6232215020340225
720346320253656
oct2732243366271
9636062026208
10201101012153
11783173079a8
1232b843a4675
1315c6b465762
149a3a404c2d
15536ee5a138
hex2ed28decb9

201101012153 has 2 divisors, whose sum is σ = 201101012154. Its totient is φ = 201101012152.

The previous prime is 201101012041. The next prime is 201101012171. The reversal of 201101012153 is 351210101102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 199998572944 + 1102439209 = 447212^2 + 33203^2 .

It is a cyclic number.

It is not a de Polignac number, because 201101012153 - 226 = 201033903289 is a prime.

It is a super-2 number, since 2×2011010121532 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (201101012953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100550506076 + 100550506077.

It is an arithmetic number, because the mean of its divisors is an integer number (100550506077).

Almost surely, 2201101012153 is an apocalyptic number.

It is an amenable number.

201101012153 is a deficient number, since it is larger than the sum of its proper divisors (1).

201101012153 is an equidigital number, since it uses as much as digits as its factorization.

201101012153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 201101012153 its reverse (351210101102), we get a palindrome (552311113255).

The spelling of 201101012153 in words is "two hundred one billion, one hundred one million, twelve thousand, one hundred fifty-three".