Base | Representation |
---|---|
bin | 11101010000111001100… |
… | …011000111010110101011 |
3 | 21010020202202111000100102 |
4 | 131100321203013112223 |
5 | 230422022102413003 |
6 | 4135502331500015 |
7 | 265201464445316 |
oct | 35207143072653 |
9 | 7106682430312 |
10 | 2011010201003 |
11 | 705956916861 |
12 | 2858b72b760b |
13 | 117839620bcb |
14 | 6d494c5797d |
15 | 3749e8d4588 |
hex | 1d4398c75ab |
2011010201003 has 2 divisors, whose sum is σ = 2011010201004. Its totient is φ = 2011010201002.
The previous prime is 2011010200993. The next prime is 2011010201029. The reversal of 2011010201003 is 3001020101102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2011010201003 - 222 = 2011006006699 is a prime.
It is not a weakly prime, because it can be changed into another prime (2011010209003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005505100501 + 1005505100502.
It is an arithmetic number, because the mean of its divisors is an integer number (1005505100502).
Almost surely, 22011010201003 is an apocalyptic number.
2011010201003 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011010201003 is an equidigital number, since it uses as much as digits as its factorization.
2011010201003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 2011010201003 its reverse (3001020101102), we get a palindrome (5012030302105).
Subtracting 2011010201003 from its reverse (3001020101102), we obtain a palindrome (990009900099).
The spelling of 2011010201003 in words is "two trillion, eleven billion, ten million, two hundred one thousand, three".
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