Base | Representation |
---|---|
bin | 101101101110011001111010… |
… | …111111001010011000010011 |
3 | 222101001001212222222110100102 |
4 | 231232121322333022120103 |
5 | 202324314343130030001 |
6 | 1551412311214243015 |
7 | 60234032540664323 |
oct | 5556317277123023 |
9 | 871031788873312 |
10 | 201101022111251 |
11 | 5909351231a689 |
12 | 1a67a8854b646b |
13 | 882998ba466c2 |
14 | 37934acb53283 |
15 | 183b17463ce6b |
hex | b6e67afca613 |
201101022111251 has 2 divisors, whose sum is σ = 201101022111252. Its totient is φ = 201101022111250.
The previous prime is 201101022111169. The next prime is 201101022111257. The reversal of 201101022111251 is 152111220101102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201101022111251 is a prime.
It is not a weakly prime, because it can be changed into another prime (201101022111257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100550511055625 + 100550511055626.
It is an arithmetic number, because the mean of its divisors is an integer number (100550511055626).
Almost surely, 2201101022111251 is an apocalyptic number.
201101022111251 is a deficient number, since it is larger than the sum of its proper divisors (1).
201101022111251 is an equidigital number, since it uses as much as digits as its factorization.
201101022111251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 20.
Adding to 201101022111251 its reverse (152111220101102), we get a palindrome (353212242212353).
The spelling of 201101022111251 in words is "two hundred one trillion, one hundred one billion, twenty-two million, one hundred eleven thousand, two hundred fifty-one".
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