Base | Representation |
---|---|
bin | 1001001001010001111111… |
… | …11110011100000000110011 |
3 | 2122012111201011020211200012 |
4 | 10210220333332130000303 |
5 | 10113441001203242042 |
6 | 110434242422045135 |
7 | 4143623164256354 |
oct | 444507776340063 |
9 | 78174634224605 |
10 | 20110110212147 |
11 | 6453716a4416a |
12 | 23095832797ab |
13 | b2b4b558b717 |
14 | 4d7497d2dd2b |
15 | 24d19b99de82 |
hex | 124a3ff9c033 |
20110110212147 has 2 divisors, whose sum is σ = 20110110212148. Its totient is φ = 20110110212146.
The previous prime is 20110110212099. The next prime is 20110110212261. The reversal of 20110110212147 is 74121201101102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20110110212147 - 212 = 20110110208051 is a prime.
It is not a weakly prime, because it can be changed into another prime (20110110215147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055055106073 + 10055055106074.
It is an arithmetic number, because the mean of its divisors is an integer number (10055055106074).
Almost surely, 220110110212147 is an apocalyptic number.
20110110212147 is a deficient number, since it is larger than the sum of its proper divisors (1).
20110110212147 is an equidigital number, since it uses as much as digits as its factorization.
20110110212147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 20110110212147 its reverse (74121201101102), we get a palindrome (94231311313249).
The spelling of 20110110212147 in words is "twenty trillion, one hundred ten billion, one hundred ten million, two hundred twelve thousand, one hundred forty-seven".
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