Base | Representation |
---|---|
bin | 10010101110101010… |
… | …000001110000100001 |
3 | 1220220111202001020222 |
4 | 102232222001300201 |
5 | 312141142401032 |
6 | 13123301412425 |
7 | 1311230134226 |
oct | 225652016041 |
9 | 56814661228 |
10 | 20110122017 |
11 | 858a704357 |
12 | 3a92a0a115 |
13 | 1b864536ab |
14 | d8ab8d94d |
15 | 7ca76ea12 |
hex | 4aea81c21 |
20110122017 has 2 divisors, whose sum is σ = 20110122018. Its totient is φ = 20110122016.
The previous prime is 20110121971. The next prime is 20110122029. The reversal of 20110122017 is 71022101102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20084274961 + 25847056 = 141719^2 + 5084^2 .
It is a cyclic number.
It is not a de Polignac number, because 20110122017 - 28 = 20110121761 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20110121986 and 20110122004.
It is not a weakly prime, because it can be changed into another prime (20110122037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055061008 + 10055061009.
It is an arithmetic number, because the mean of its divisors is an integer number (10055061009).
Almost surely, 220110122017 is an apocalyptic number.
It is an amenable number.
20110122017 is a deficient number, since it is larger than the sum of its proper divisors (1).
20110122017 is an equidigital number, since it uses as much as digits as its factorization.
20110122017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 20110122017 its reverse (71022101102), we get a palindrome (91132223119).
The spelling of 20110122017 in words is "twenty billion, one hundred ten million, one hundred twenty-two thousand, seventeen".
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