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201102014153 is a prime number
BaseRepresentation
bin1011101101001010011…
…1010011011011001001
3201020002010220210201102
42323102213103123021
511243324103423103
6232215054031145
720346331626155
oct2732247233311
9636063823642
10201102014153
11783179317a7
1232b847a84b5
1315c6b726861
149a3a5c6065
1553700a6e88
hex2ed29d36c9

201102014153 has 2 divisors, whose sum is σ = 201102014154. Its totient is φ = 201102014152.

The previous prime is 201102014107. The next prime is 201102014171. The reversal of 201102014153 is 351410201102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129018892864 + 72083121289 = 359192^2 + 268483^2 .

It is a cyclic number.

It is not a de Polignac number, because 201102014153 - 214 = 201101997769 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (201102011153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100551007076 + 100551007077.

It is an arithmetic number, because the mean of its divisors is an integer number (100551007077).

Almost surely, 2201102014153 is an apocalyptic number.

It is an amenable number.

201102014153 is a deficient number, since it is larger than the sum of its proper divisors (1).

201102014153 is an equidigital number, since it uses as much as digits as its factorization.

201102014153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 201102014153 its reverse (351410201102), we get a palindrome (552512215255).

The spelling of 201102014153 in words is "two hundred one billion, one hundred two million, fourteen thousand, one hundred fifty-three".