Base | Representation |
---|---|
bin | 1011101101001010011… |
… | …1010100111001010001 |
3 | 201020002010221002222112 |
4 | 2323102213110321101 |
5 | 11243324104121202 |
6 | 232215054115105 |
7 | 20346331652552 |
oct | 2732247247121 |
9 | 636063832875 |
10 | 201102020177 |
11 | 78317936283 |
12 | 32b847aba95 |
13 | 15c6b729516 |
14 | 9a3a5c8329 |
15 | 53700a8b52 |
hex | 2ed29d4e51 |
201102020177 has 2 divisors, whose sum is σ = 201102020178. Its totient is φ = 201102020176.
The previous prime is 201102020137. The next prime is 201102020213. The reversal of 201102020177 is 771020201102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 137226534481 + 63875485696 = 370441^2 + 252736^2 .
It is a cyclic number.
It is not a de Polignac number, because 201102020177 - 26 = 201102020113 is a prime.
It is a super-2 number, since 2×2011020201772 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (201102020107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100551010088 + 100551010089.
It is an arithmetic number, because the mean of its divisors is an integer number (100551010089).
Almost surely, 2201102020177 is an apocalyptic number.
It is an amenable number.
201102020177 is a deficient number, since it is larger than the sum of its proper divisors (1).
201102020177 is an equidigital number, since it uses as much as digits as its factorization.
201102020177 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 392, while the sum is 23.
Adding to 201102020177 its reverse (771020201102), we get a palindrome (972122221279).
The spelling of 201102020177 in words is "two hundred one billion, one hundred two million, twenty thousand, one hundred seventy-seven".
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