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201102102091147 is a prime number
BaseRepresentation
bin101101101110011010111011…
…010110111101010110001011
3222101001011200021011010020211
4231232122323112331112023
5202324324101113404042
61551413010314101551
760234101363445625
oct5556327326752613
9871034607133224
10201102102091147
1159093a16a00554
121a67ab2711a8b7
138829b01707a6a
14379357235dc15
15183b1d936c017
hexb6e6bb5bd58b

201102102091147 has 2 divisors, whose sum is σ = 201102102091148. Its totient is φ = 201102102091146.

The previous prime is 201102102091123. The next prime is 201102102091157. The reversal of 201102102091147 is 741190201201102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201102102091147 is a prime.

It is a super-2 number, since 2×2011021020911472 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (201102102091117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100551051045573 + 100551051045574.

It is an arithmetic number, because the mean of its divisors is an integer number (100551051045574).

Almost surely, 2201102102091147 is an apocalyptic number.

201102102091147 is a deficient number, since it is larger than the sum of its proper divisors (1).

201102102091147 is an equidigital number, since it uses as much as digits as its factorization.

201102102091147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 31.

Adding to 201102102091147 its reverse (741190201201102), we get a palindrome (942292303292249).

The spelling of 201102102091147 in words is "two hundred one trillion, one hundred two billion, one hundred two million, ninety-one thousand, one hundred forty-seven".