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20110211202015 = 3251140626689297
BaseRepresentation
bin1001001001010010001011…
…11111101011101111011111
32122012111222012021122201200
410210221011333223233133
510113441203031431030
6110434300430410543
74143625531543434
oct444510577535737
978174865248650
1020110211202015
116453768a51370
1223095b1060a53
13b2b50048a93c
144d74a74dbb8b
1524d1a579bd60
hex124a45febbdf

20110211202015 has 24 divisors (see below), whose sum is σ = 38026581182928. Its totient is φ = 9750405431040.

The previous prime is 20110211202001. The next prime is 20110211202031. The reversal of 20110211202015 is 51020211201102.

It is a de Polignac number, because none of the positive numbers 2k-20110211202015 is a prime.

It is a super-2 number, since 2×201102112020152 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 20313344154 + ... + 20313345143.

It is an arithmetic number, because the mean of its divisors is an integer number (1584440882622).

Almost surely, 220110211202015 is an apocalyptic number.

20110211202015 is a deficient number, since it is larger than the sum of its proper divisors (17916369980913).

20110211202015 is a wasteful number, since it uses less digits than its factorization.

20110211202015 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40626689319 (or 40626689316 counting only the distinct ones).

The product of its (nonzero) digits is 80, while the sum is 18.

Adding to 20110211202015 its reverse (51020211201102), we get a palindrome (71130422403117).

The spelling of 20110211202015 in words is "twenty trillion, one hundred ten billion, two hundred eleven million, two hundred two thousand, fifteen".

Divisors: 1 3 5 9 11 15 33 45 55 99 165 495 40626689297 121880067891 203133446485 365640203673 446893582267 609400339455 1340680746801 1828201018365 2234467911335 4022042240403 6703403734005 20110211202015