Base | Representation |
---|---|
bin | 101101101110011010111011… |
… | …111101100100000001101011 |
3 | 222101001011200222012021011002 |
4 | 231232122323331210001223 |
5 | 202324324111211223201 |
6 | 1551413011315025215 |
7 | 60234101545455002 |
oct | 5556327375440153 |
9 | 871034628167132 |
10 | 201102112211051 |
11 | 59093a21692807 |
12 | 1a67ab2a59b20b |
13 | 8829b0383c07c |
14 | 3793573835c39 |
15 | 183b1da1ba76b |
hex | b6e6bbf6406b |
201102112211051 has 2 divisors, whose sum is σ = 201102112211052. Its totient is φ = 201102112211050.
The previous prime is 201102112211047. The next prime is 201102112211101. The reversal of 201102112211051 is 150112211201102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201102112211051 - 22 = 201102112211047 is a prime.
It is a super-2 number, since 2×2011021122110512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (201102112211951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100551056105525 + 100551056105526.
It is an arithmetic number, because the mean of its divisors is an integer number (100551056105526).
Almost surely, 2201102112211051 is an apocalyptic number.
201102112211051 is a deficient number, since it is larger than the sum of its proper divisors (1).
201102112211051 is an equidigital number, since it uses as much as digits as its factorization.
201102112211051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 20.
Adding to 201102112211051 its reverse (150112211201102), we get a palindrome (351214323412153).
The spelling of 201102112211051 in words is "two hundred one trillion, one hundred two billion, one hundred twelve million, two hundred eleven thousand, fifty-one".
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