20110400000113 has 4 divisors (see below), whose sum is σ = 21293364706020. Its totient is φ = 18927435294208.

The previous prime is 20110400000081. The next prime is 20110400000137. The reversal of 20110400000113 is 31100000401102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 16030678691889 + 4079721308224 = 4003833^2 + 2019832^2 .

It is a cyclic number.

It is not a de Polignac number, because 20110400000113 - 2⁵ = 20110400000081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20110400000093 and 20110400000102.

It is not an unprimeable number, because it can be changed into a prime (20110400000183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 591482352928 + ... + 591482352961.

It is an arithmetic number, because the mean of its divisors is an integer number (5323341176505).

Almost surely, 2^{20110400000113} is an apocalyptic number.

It is an amenable number.

20110400000113 is a deficient number, since it is larger than the sum of its proper divisors (1182964705907).

20110400000113 is a wasteful number, since it uses less digits than its factorization.

20110400000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1182964705906.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 20110400000113 its reverse (31100000401102), we get a palindrome (51210400401215).

The spelling of 20110400000113 in words is "twenty trillion, one hundred ten billion, four hundred million, one hundred thirteen", and thus it is an aban number.