20110400000081 has 2 divisors, whose sum is σ = 20110400000082. Its totient is φ = 20110400000080.

The previous prime is 20110399999979. The next prime is 20110400000137. The reversal of 20110400000081 is 18000000401102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13526146639681 + 6584253360400 = 3677791^2 + 2565980^2 .

It is a cyclic number.

It is not a de Polignac number, because 20110400000081 - 2²² = 20110395805777 is a prime.

It is a super-2 number, since 2×20110400000081² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20110400000381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055200000040 + 10055200000041.

It is an arithmetic number, because the mean of its divisors is an integer number (10055200000041).

Almost surely, 2^{20110400000081} is an apocalyptic number.

It is an amenable number.

20110400000081 is a deficient number, since it is larger than the sum of its proper divisors (1).

20110400000081 is an equidigital number, since it uses as much as digits as its factorization.

20110400000081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 20110400000081 its reverse (18000000401102), we get a palindrome (38110400401183).

The spelling of 20110400000081 in words is "twenty trillion, one hundred ten billion, four hundred million, eighty-one", and thus it is an aban number.