Base | Representation |
---|---|
bin | 10010101110101101… |
… | …011000000111000011 |
3 | 1220220120101122121222 |
4 | 102232231120013003 |
5 | 312141404000003 |
6 | 13123332305255 |
7 | 1311240452033 |
oct | 225655300703 |
9 | 56816348558 |
10 | 20111000003 |
11 | 8590153a66 |
12 | 3a9317222b |
13 | 1b866a0203 |
14 | d8ad3b8c3 |
15 | 7ca894c38 |
hex | 4aeb581c3 |
20111000003 has 2 divisors, whose sum is σ = 20111000004. Its totient is φ = 20111000002.
The previous prime is 20110999973. The next prime is 20111000027. The reversal of 20111000003 is 30000011102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20111000003 - 28 = 20110999747 is a prime.
It is a super-2 number, since 2×201110000032 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20111000033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055500001 + 10055500002.
It is an arithmetic number, because the mean of its divisors is an integer number (10055500002).
Almost surely, 220111000003 is an apocalyptic number.
20111000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111000003 is an equidigital number, since it uses as much as digits as its factorization.
20111000003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6, while the sum is 8.
Adding to 20111000003 its reverse (30000011102), we get a palindrome (50111011105).
The spelling of 20111000003 in words is "twenty billion, one hundred eleven million, three", and thus it is an aban number.
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