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20111104440001 is a prime number
BaseRepresentation
bin1001001001010011110110…
…01111000111011011000001
32122012121021110001211220001
410210221323033013123001
510114000020214040001
6110434525215520001
74143656626130011
oct444517317073301
978177243054801
1020111104440001
116454087185283
122309800229001
13b2b613557523
144d754ddb7c41
1524d208de0001
hex124a7b3c76c1

20111104440001 has 2 divisors, whose sum is σ = 20111104440002. Its totient is φ = 20111104440000.

The previous prime is 20111104439977. The next prime is 20111104440043. The reversal of 20111104440001 is 10004440111102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15771898818225 + 4339205621776 = 3971385^2 + 2083076^2 .

It is a cyclic number.

It is not a de Polignac number, because 20111104440001 - 213 = 20111104431809 is a prime.

It is not a weakly prime, because it can be changed into another prime (20111104446001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055552220000 + 10055552220001.

It is an arithmetic number, because the mean of its divisors is an integer number (10055552220001).

Almost surely, 220111104440001 is an apocalyptic number.

It is an amenable number.

20111104440001 is a deficient number, since it is larger than the sum of its proper divisors (1).

20111104440001 is an equidigital number, since it uses as much as digits as its factorization.

20111104440001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 128, while the sum is 19.

Adding to 20111104440001 its reverse (10004440111102), we get a palindrome (30115544551103).

The spelling of 20111104440001 in words is "twenty trillion, one hundred eleven billion, one hundred four million, four hundred forty thousand, one".