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201111100112002 = 2100555550056001
BaseRepresentation
bin101101101110100011010011…
…101011101011110010000010
3222101002000220100111221101111
4231232203103223223302002
5202330001013112041002
61551421055224553534
760234540353404603
oct5556432353536202
9871060810457344
10201111100112002
115909781406a823
121a6808186228aa
13882a906944262
143793b873bbdaa
15183b5642a73d7
hexb6e8d3aebc82

201111100112002 has 4 divisors (see below), whose sum is σ = 301666650168006. Its totient is φ = 100555550056000.

The previous prime is 201111100111991. The next prime is 201111100112057. The reversal of 201111100112002 is 200211001111102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 147191465798001 + 53919634314001 = 12132249^2 + 7342999^2 .

It is a super-3 number, since 3×2011111001120023 (a number of 44 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50277775027999 + ... + 50277775028002.

Almost surely, 2201111100112002 is an apocalyptic number.

201111100112002 is a deficient number, since it is larger than the sum of its proper divisors (100555550056004).

201111100112002 is a wasteful number, since it uses less digits than its factorization.

201111100112002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100555550056003.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 201111100112002 its reverse (200211001111102), we get a palindrome (401322101223104).

The spelling of 201111100112002 in words is "two hundred one trillion, one hundred eleven billion, one hundred million, one hundred twelve thousand, two".

Divisors: 1 2 100555550056001 201111100112002