Base | Representation |
---|---|
bin | 1001001001010011110111… |
… | …01100011000000000100001 |
3 | 2122012121021222111112022021 |
4 | 10210221323230120000201 |
5 | 10114000024200010423 |
6 | 110434530052141441 |
7 | 4143660051253603 |
oct | 444517354300041 |
9 | 78177258445267 |
10 | 20111112110113 |
11 | 6454090543a12 |
12 | 2309802907881 |
13 | b2b61501175b |
14 | 4d7551013173 |
15 | 24d20990795d |
hex | 124a7bb18021 |
20111112110113 has 2 divisors, whose sum is σ = 20111112110114. Its totient is φ = 20111112110112.
The previous prime is 20111112110083. The next prime is 20111112110161. The reversal of 20111112110113 is 31101121111102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18479956564224 + 1631155545889 = 4298832^2 + 1277167^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20111112110113 is a prime.
It is not a weakly prime, because it can be changed into another prime (20111112110213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055556055056 + 10055556055057.
It is an arithmetic number, because the mean of its divisors is an integer number (10055556055057).
Almost surely, 220111112110113 is an apocalyptic number.
It is an amenable number.
20111112110113 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111112110113 is an equidigital number, since it uses as much as digits as its factorization.
20111112110113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 16.
Adding to 20111112110113 its reverse (31101121111102), we get a palindrome (51212233221215).
The spelling of 20111112110113 in words is "twenty trillion, one hundred eleven billion, one hundred twelve million, one hundred ten thousand, one hundred thirteen".
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