Base | Representation |
---|---|
bin | 101101101110100011011010… |
… | …010111010001100001110101 |
3 | 222101002001012011102201002122 |
4 | 231232203122113101201311 |
5 | 202330001230310431401 |
6 | 1551421114311245325 |
7 | 60234543214223105 |
oct | 5556433227214165 |
9 | 871061164381078 |
10 | 201111212202101 |
11 | 59097871369773 |
12 | 1a68084a079845 |
13 | 882a923c2ba66 |
14 | 3793b98239205 |
15 | 183b56e04921b |
hex | b6e8da5d1875 |
201111212202101 has 4 divisors (see below), whose sum is σ = 201239226979104. Its totient is φ = 200983197425100.
The previous prime is 201111212202053. The next prime is 201111212202191. The reversal of 201111212202101 is 101202212111102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 201111212202101 - 210 = 201111212201077 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 201111212202101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201111212202191) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64007386145 + ... + 64007389286.
It is an arithmetic number, because the mean of its divisors is an integer number (50309806744776).
Almost surely, 2201111212202101 is an apocalyptic number.
It is an amenable number.
201111212202101 is a deficient number, since it is larger than the sum of its proper divisors (128014777003).
201111212202101 is a wasteful number, since it uses less digits than its factorization.
201111212202101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 128014777002.
The product of its (nonzero) digits is 32, while the sum is 17.
Adding to 201111212202101 its reverse (101202212111102), we get a palindrome (302313424313203).
Subtracting from 201111212202101 its reverse (101202212111102), we obtain a palindrome (99909000090999).
The spelling of 201111212202101 in words is "two hundred one trillion, one hundred eleven billion, two hundred twelve million, two hundred two thousand, one hundred one".
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