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20111121300044 = 2213138380002481
BaseRepresentation
bin1001001001010011111000…
…01111011011101001001100
32122012121022121210102112002
410210221330033123221030
510114000034023100134
6110434531021131432
74143660222340445
oct444517417335114
978177277712462
1020111121300044
1164540957504a5
1223098059b9b78
13b2b616bab698
144d75523262cc
1524d20a62087e
hex124a7c3dba4c

20111121300044 has 12 divisors (see below), whose sum is σ = 35463122293368. Its totient is φ = 9978800644800.

The previous prime is 20111121300043. The next prime is 20111121300089. The reversal of 20111121300044 is 44000312111102.

It is a junction number, because it is equal to n+sod(n) for n = 20111121299989 and 20111121300025.

It is not an unprimeable number, because it can be changed into a prime (20111121300043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19190000717 + ... + 19190001764.

It is an arithmetic number, because the mean of its divisors is an integer number (2955260191114).

Almost surely, 220111121300044 is an apocalyptic number.

It is an amenable number.

20111121300044 is a deficient number, since it is larger than the sum of its proper divisors (15352000993324).

20111121300044 is a wasteful number, since it uses less digits than its factorization.

20111121300044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38380002616 (or 38380002614 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 20111121300044 its reverse (44000312111102), we get a palindrome (64111433411146).

The spelling of 20111121300044 in words is "twenty trillion, one hundred eleven billion, one hundred twenty-one million, three hundred thousand, forty-four".

Divisors: 1 2 4 131 262 524 38380002481 76760004962 153520009924 5027780325011 10055560650022 20111121300044