Base | Representation |
---|---|
bin | 11101010000111111110… |
… | …000101110011100110011 |
3 | 21010021001000121111211002 |
4 | 131100333300232130303 |
5 | 230422230243313212 |
6 | 4135520533512215 |
7 | 265204201422551 |
oct | 35207760563463 |
9 | 7107030544732 |
10 | 2011114432307 |
11 | 7059aa738332 |
12 | 2859261a266b |
13 | 1178550b6636 |
14 | 6d4a4a2abd1 |
15 | 374a8b22ac2 |
hex | 1d43fc2e733 |
2011114432307 has 2 divisors, whose sum is σ = 2011114432308. Its totient is φ = 2011114432306.
The previous prime is 2011114432289. The next prime is 2011114432351. The reversal of 2011114432307 is 7032344111102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2011114432307 - 214 = 2011114415923 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2011114432307.
It is not a weakly prime, because it can be changed into another prime (2011114432387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005557216153 + 1005557216154.
It is an arithmetic number, because the mean of its divisors is an integer number (1005557216154).
Almost surely, 22011114432307 is an apocalyptic number.
2011114432307 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011114432307 is an equidigital number, since it uses as much as digits as its factorization.
2011114432307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 2011114432307 its reverse (7032344111102), we get a palindrome (9043458543409).
The spelling of 2011114432307 in words is "two trillion, eleven billion, one hundred fourteen million, four hundred thirty-two thousand, three hundred seven".
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