Base | Representation |
---|---|
bin | 1001001001010100000011… |
… | …01001110011110110010011 |
3 | 2122012121112221122121000212 |
4 | 10210222001221303312103 |
5 | 10114000230244213021 |
6 | 110434544023234335 |
7 | 4143662404210343 |
oct | 444520151636623 |
9 | 78177487577025 |
10 | 20111212101011 |
11 | 6454131a29619 |
12 | 23098302a89ab |
13 | b2b62c951075 |
14 | 4d7560400d23 |
15 | 24d2135a985b |
hex | 124a81a73d93 |
20111212101011 has 2 divisors, whose sum is σ = 20111212101012. Its totient is φ = 20111212101010.
The previous prime is 20111212100983. The next prime is 20111212101017. The reversal of 20111212101011 is 11010121211102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20111212101011 - 210 = 20111212099987 is a prime.
It is not a weakly prime, because it can be changed into another prime (20111212101017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055606050505 + 10055606050506.
It is an arithmetic number, because the mean of its divisors is an integer number (10055606050506).
Almost surely, 220111212101011 is an apocalyptic number.
20111212101011 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111212101011 is an equidigital number, since it uses as much as digits as its factorization.
20111212101011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 20111212101011 its reverse (11010121211102), we get a palindrome (31121333312113).
The spelling of 20111212101011 in words is "twenty trillion, one hundred eleven billion, two hundred twelve million, one hundred one thousand, eleven".
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