20111220193 has 2 divisors, whose sum is σ = 20111220194. Its totient is φ = 20111220192.

The previous prime is 20111220161. The next prime is 20111220211. The reversal of 20111220193 is 39102211102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20091078049 + 20142144 = 141743^2 + 4488^2 .

It is a cyclic number.

It is not a de Polignac number, because 20111220193 - 2⁵ = 20111220161 is a prime.

It is a super-2 number, since 2×20111220193² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20111226193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055610096 + 10055610097.

It is an arithmetic number, because the mean of its divisors is an integer number (10055610097).

Almost surely, 2^20111220193 is an apocalyptic number.

It is an amenable number.

20111220193 is a deficient number, since it is larger than the sum of its proper divisors (1).

20111220193 is an equidigital number, since it uses as much as digits as its factorization.

20111220193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 20111220193 its reverse (39102211102), we get a palindrome (59213431295).

The spelling of 20111220193 in words is "twenty billion, one hundred eleven million, two hundred twenty thousand, one hundred ninety-three".