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20111331113 is a prime number
BaseRepresentation
bin10010101110101110…
…101000111100101001
31220220121000110211022
4102232232220330221
5312142000043423
613123343342225
71311243331256
oct225656507451
956817013738
1020111331113
11859035a805
123a932b1975
131b86787b33
14d8adc642d
157ca90cdc8
hex4aeba8f29

20111331113 has 2 divisors, whose sum is σ = 20111331114. Its totient is φ = 20111331112.

The previous prime is 20111331101. The next prime is 20111331181. The reversal of 20111331113 is 31113311102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15238174249 + 4873156864 = 123443^2 + 69808^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20111331113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20111331091 and 20111331100.

It is not a weakly prime, because it can be changed into another prime (20111339113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055665556 + 10055665557.

It is an arithmetic number, because the mean of its divisors is an integer number (10055665557).

Almost surely, 220111331113 is an apocalyptic number.

It is an amenable number.

20111331113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20111331113 is an equidigital number, since it uses as much as digits as its factorization.

20111331113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 20111331113 its reverse (31113311102), we get a palindrome (51224642215).

The spelling of 20111331113 in words is "twenty billion, one hundred eleven million, three hundred thirty-one thousand, one hundred thirteen".