Base | Representation |
---|---|
bin | 10010101110110001… |
… | …001100010101000011 |
3 | 1220220122021110210212 |
4 | 102232301030111003 |
5 | 312142133002243 |
6 | 13123405544335 |
7 | 1311252116312 |
oct | 225661142503 |
9 | 56818243725 |
10 | 20112000323 |
11 | 8590777578 |
12 | 3a935750ab |
13 | 1b8696060c |
14 | d8b11c279 |
15 | 7ca9e1318 |
hex | 4aec4c543 |
20112000323 has 4 divisors (see below), whose sum is σ = 20112587880. Its totient is φ = 20111412768.
The previous prime is 20112000319. The next prime is 20112000371. The reversal of 20112000323 is 32300021102.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32300021102 = 2 ⋅16150010551.
It is a cyclic number.
It is not a de Polignac number, because 20112000323 - 22 = 20112000319 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20112000298 and 20112000307.
It is not an unprimeable number, because it can be changed into a prime (20112006323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 239033 + ... + 312026.
It is an arithmetic number, because the mean of its divisors is an integer number (5028146970).
Almost surely, 220112000323 is an apocalyptic number.
20112000323 is a deficient number, since it is larger than the sum of its proper divisors (587557).
20112000323 is an equidigital number, since it uses as much as digits as its factorization.
20112000323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 587556.
The product of its (nonzero) digits is 72, while the sum is 14.
Adding to 20112000323 its reverse (32300021102), we get a palindrome (52412021425).
The spelling of 20112000323 in words is "twenty billion, one hundred twelve million, three hundred twenty-three", and thus it is an aban number.
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