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201120113 is a prime number
BaseRepresentation
bin10111111110011…
…01100101110001
3112000102221221002
423333031211301
5402441320423
631542411345
74661331005
oct1377154561
9460387832
10201120113
11a3588577
1257430b55
133288a0ac
141c9d4705
15129cb228
hexbfcd971

201120113 has 2 divisors, whose sum is σ = 201120114. Its totient is φ = 201120112.

The previous prime is 201120109. The next prime is 201120137. The reversal of 201120113 is 311021102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 183412849 + 17707264 = 13543^2 + 4208^2 .

It is a cyclic number.

It is not a de Polignac number, because 201120113 - 22 = 201120109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201120094 and 201120103.

It is not a weakly prime, because it can be changed into another prime (201120103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100560056 + 100560057.

It is an arithmetic number, because the mean of its divisors is an integer number (100560057).

Almost surely, 2201120113 is an apocalyptic number.

It is an amenable number.

201120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

201120113 is an equidigital number, since it uses as much as digits as its factorization.

201120113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 201120113 is about 14181.6823050018. The cubic root of 201120113 is about 585.8932592607.

Adding to 201120113 its reverse (311021102), we get a palindrome (512141215).

The spelling of 201120113 in words is "two hundred one million, one hundred twenty thousand, one hundred thirteen".