Base | Representation |
---|---|
bin | 1011101101001110110… |
… | …0011000000111001011 |
3 | 201020010101222202001011 |
4 | 2323103230120013023 |
5 | 11243343222340131 |
6 | 232220542104351 |
7 | 20346641552515 |
oct | 2732354300713 |
9 | 636111882034 |
10 | 201120121291 |
11 | 78327079981 |
12 | 32b8a87b0b7 |
13 | 15c723c653b |
14 | 9a3cb7abb5 |
15 | 53719820b1 |
hex | 2ed3b181cb |
201120121291 has 2 divisors, whose sum is σ = 201120121292. Its totient is φ = 201120121290.
The previous prime is 201120121219. The next prime is 201120121297. The reversal of 201120121291 is 192121021102.
Together with previous prime (201120121219) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201120121291 - 213 = 201120113099 is a prime.
It is not a weakly prime, because it can be changed into another prime (201120121297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100560060645 + 100560060646.
It is an arithmetic number, because the mean of its divisors is an integer number (100560060646).
Almost surely, 2201120121291 is an apocalyptic number.
201120121291 is a deficient number, since it is larger than the sum of its proper divisors (1).
201120121291 is an equidigital number, since it uses as much as digits as its factorization.
201120121291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 22.
Adding to 201120121291 its reverse (192121021102), we get a palindrome (393241142393).
The spelling of 201120121291 in words is "two hundred one billion, one hundred twenty million, one hundred twenty-one thousand, two hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •