Base | Representation |
---|---|
bin | 11101010001000101011… |
… | …101010010011011100001 |
3 | 21010021021200102212011212 |
4 | 131101011131102123201 |
5 | 230422424230000342 |
6 | 4135534230115505 |
7 | 265206441635054 |
oct | 35210535223341 |
9 | 7107250385155 |
10 | 2011210000097 |
11 | 705a49681881 |
12 | 2859521abb95 |
13 | 11786bb3791c |
14 | 6d4b35c6a9b |
15 | 374b21ee182 |
hex | 1d4457526e1 |
2011210000097 has 2 divisors, whose sum is σ = 2011210000098. Its totient is φ = 2011210000096.
The previous prime is 2011210000067. The next prime is 2011210000123. The reversal of 2011210000097 is 7900000121102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1936483763776 + 74726236321 = 1391576^2 + 273361^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2011210000097 is a prime.
It is not a weakly prime, because it can be changed into another prime (2011210000067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005605000048 + 1005605000049.
It is an arithmetic number, because the mean of its divisors is an integer number (1005605000049).
Almost surely, 22011210000097 is an apocalyptic number.
It is an amenable number.
2011210000097 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011210000097 is an equidigital number, since it uses as much as digits as its factorization.
2011210000097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 23.
Adding to 2011210000097 its reverse (7900000121102), we get a palindrome (9911210121199).
The spelling of 2011210000097 in words is "two trillion, eleven billion, two hundred ten million, ninety-seven", and thus it is an aban number.
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