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20112100121103 = 313748934550173
BaseRepresentation
bin1001001001010101101101…
…00101010101101000001111
32122012200211211121200120220
410210222312211111220033
510114004040112333403
6110435212104442423
74144023406232244
oct444526645255017
978180754550526
1020112100121103
116454548219221
122309a39779413
13b2b741911943
144d760631d5cb
1524d26651b953
hex124ab6955a0f

20112100121103 has 8 divisors (see below), whose sum is σ = 27011871696048. Its totient is φ = 13310197646784.

The previous prime is 20112100121089. The next prime is 20112100121129. The reversal of 20112100121103 is 30112100121102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 20112100121103 - 213 = 20112100112911 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20112100120103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24467274676 + ... + 24467275497.

It is an arithmetic number, because the mean of its divisors is an integer number (3376483962006).

Almost surely, 220112100121103 is an apocalyptic number.

20112100121103 is a deficient number, since it is larger than the sum of its proper divisors (6899771574945).

20112100121103 is a wasteful number, since it uses less digits than its factorization.

20112100121103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48934550313.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 20112100121103 its reverse (30112100121102), we get a palindrome (50224200242205).

Subtracting 20112100121103 from its reverse (30112100121102), we obtain a palindrome (9999999999999).

The spelling of 20112100121103 in words is "twenty trillion, one hundred twelve billion, one hundred million, one hundred twenty-one thousand, one hundred three".

Divisors: 1 3 137 411 48934550173 146803650519 6704033373701 20112100121103