Base | Representation |
---|---|
bin | 1001001001010101101101… |
… | …00101010101101000001111 |
3 | 2122012200211211121200120220 |
4 | 10210222312211111220033 |
5 | 10114004040112333403 |
6 | 110435212104442423 |
7 | 4144023406232244 |
oct | 444526645255017 |
9 | 78180754550526 |
10 | 20112100121103 |
11 | 6454548219221 |
12 | 2309a39779413 |
13 | b2b741911943 |
14 | 4d760631d5cb |
15 | 24d26651b953 |
hex | 124ab6955a0f |
20112100121103 has 8 divisors (see below), whose sum is σ = 27011871696048. Its totient is φ = 13310197646784.
The previous prime is 20112100121089. The next prime is 20112100121129. The reversal of 20112100121103 is 30112100121102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 20112100121103 - 213 = 20112100112911 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20112100120103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24467274676 + ... + 24467275497.
It is an arithmetic number, because the mean of its divisors is an integer number (3376483962006).
Almost surely, 220112100121103 is an apocalyptic number.
20112100121103 is a deficient number, since it is larger than the sum of its proper divisors (6899771574945).
20112100121103 is a wasteful number, since it uses less digits than its factorization.
20112100121103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48934550313.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 20112100121103 its reverse (30112100121102), we get a palindrome (50224200242205).
Subtracting 20112100121103 from its reverse (30112100121102), we obtain a palindrome (9999999999999).
The spelling of 20112100121103 in words is "twenty trillion, one hundred twelve billion, one hundred million, one hundred twenty-one thousand, one hundred three".
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