Base | Representation |
---|---|
bin | 101101101110101100100010… |
… | …011011001001000001111011 |
3 | 222101002222111001210210201211 |
4 | 231232230202123021001323 |
5 | 202330131312321010021 |
6 | 1551425414512023551 |
7 | 60235341100451536 |
oct | 5556544233110173 |
9 | 871088431723654 |
10 | 201121011110011 |
11 | 590a0a3a615273 |
12 | 1a682723831bb7 |
13 | 882b82606bb15 |
14 | 37944477b3a1d |
15 | 183b9444343e1 |
hex | b6eb226c907b |
201121011110011 has 2 divisors, whose sum is σ = 201121011110012. Its totient is φ = 201121011110010.
The previous prime is 201121011109979. The next prime is 201121011110017. The reversal of 201121011110011 is 110011110121102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201121011110011 - 25 = 201121011109979 is a prime.
It is a super-2 number, since 2×2011210111100112 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 201121011109973 and 201121011110000.
It is not a weakly prime, because it can be changed into another prime (201121011110017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100560505555005 + 100560505555006.
It is an arithmetic number, because the mean of its divisors is an integer number (100560505555006).
Almost surely, 2201121011110011 is an apocalyptic number.
201121011110011 is a deficient number, since it is larger than the sum of its proper divisors (1).
201121011110011 is an equidigital number, since it uses as much as digits as its factorization.
201121011110011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 201121011110011 its reverse (110011110121102), we get a palindrome (311132121231113).
The spelling of 201121011110011 in words is "two hundred one trillion, one hundred twenty-one billion, eleven million, one hundred ten thousand, eleven".
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