Base | Representation |
---|---|
bin | 11101010001000101011… |
… | …110000110011011101111 |
3 | 21010021021200211200100222 |
4 | 131101011132012123233 |
5 | 230422424303304403 |
6 | 4135534234441555 |
7 | 265206443513060 |
oct | 35210536063357 |
9 | 7107250750328 |
10 | 2011210213103 |
11 | 705a49807913 |
12 | 2859522932bb |
13 | 11786bbb0870 |
14 | 6d4b3640567 |
15 | 374b2242338 |
hex | 1d4457866ef |
2011210213103 has 32 divisors (see below), whose sum is σ = 2506063722624. Its totient is φ = 1571651407872.
The previous prime is 2011210213097. The next prime is 2011210213127. The reversal of 2011210213103 is 3013120121102.
It is not a de Polignac number, because 2011210213103 - 24 = 2011210213087 is a prime.
It is a super-3 number, since 3×20112102131033 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2011210213303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2046551 + ... + 2865447.
It is an arithmetic number, because the mean of its divisors is an integer number (78314491332).
Almost surely, 22011210213103 is an apocalyptic number.
2011210213103 is a deficient number, since it is larger than the sum of its proper divisors (494853509521).
2011210213103 is a wasteful number, since it uses less digits than its factorization.
2011210213103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 819251.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 2011210213103 its reverse (3013120121102), we get a palindrome (5024330334205).
The spelling of 2011210213103 in words is "two trillion, eleven billion, two hundred ten million, two hundred thirteen thousand, one hundred three".
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