Base | Representation |
---|---|
bin | 11101010001000101100… |
… | …100111111110101101001 |
3 | 21010021021211020112110201 |
4 | 131101011210333311221 |
5 | 230422430234133342 |
6 | 4135534341312201 |
7 | 265206465053146 |
oct | 35210544776551 |
9 | 7107254215421 |
10 | 2011212021097 |
11 | 705a4a832224 |
12 | 285952a05661 |
13 | 11786c394796 |
14 | 6d4b39913cd |
15 | 374b249cdb7 |
hex | 1d44593fd69 |
2011212021097 has 2 divisors, whose sum is σ = 2011212021098. Its totient is φ = 2011212021096.
The previous prime is 2011212021083. The next prime is 2011212021151. The reversal of 2011212021097 is 7901202121102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1531799800281 + 479412220816 = 1237659^2 + 692396^2 .
It is a cyclic number.
It is not a de Polignac number, because 2011212021097 - 223 = 2011203632489 is a prime.
It is not a weakly prime, because it can be changed into another prime (2011212021697) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005606010548 + 1005606010549.
It is an arithmetic number, because the mean of its divisors is an integer number (1005606010549).
Almost surely, 22011212021097 is an apocalyptic number.
It is an amenable number.
2011212021097 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011212021097 is an equidigital number, since it uses as much as digits as its factorization.
2011212021097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 28.
Adding to 2011212021097 its reverse (7901202121102), we get a palindrome (9912414142199).
The spelling of 2011212021097 in words is "two trillion, eleven billion, two hundred twelve million, twenty-one thousand, ninety-seven".
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