Base | Representation |
---|---|
bin | 1001001001010111100100… |
… | …11000101011001100010001 |
3 | 2122012210102202112021211211 |
4 | 10210223302120223030101 |
5 | 10114013113434401023 |
6 | 110435455425140121 |
7 | 4144060311243235 |
oct | 444536230531421 |
9 | 78183382467754 |
10 | 20113103434513 |
11 | 6454a125a5461 |
12 | 230a07978a641 |
13 | b2b87173c00b |
14 | 4d769d6905c5 |
15 | 24d2c4654a0d |
hex | 124af262b311 |
20113103434513 has 2 divisors, whose sum is σ = 20113103434514. Its totient is φ = 20113103434512.
The previous prime is 20113103434507. The next prime is 20113103434573. The reversal of 20113103434513 is 31543430131102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18032490475024 + 2080612959489 = 4246468^2 + 1442433^2 .
It is a cyclic number.
It is not a de Polignac number, because 20113103434513 - 25 = 20113103434481 is a prime.
It is not a weakly prime, because it can be changed into another prime (20113103434573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10056551717256 + 10056551717257.
It is an arithmetic number, because the mean of its divisors is an integer number (10056551717257).
Almost surely, 220113103434513 is an apocalyptic number.
It is an amenable number.
20113103434513 is a deficient number, since it is larger than the sum of its proper divisors (1).
20113103434513 is an equidigital number, since it uses as much as digits as its factorization.
20113103434513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 20113103434513 its reverse (31543430131102), we get a palindrome (51656533565615).
The spelling of 20113103434513 in words is "twenty trillion, one hundred thirteen billion, one hundred three million, four hundred thirty-four thousand, five hundred thirteen".
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