Base | Representation |
---|---|
bin | 1011101101010001011… |
… | …0110000100000001101 |
3 | 201020011011220012000221 |
4 | 2323110112300200031 |
5 | 11243404043344440 |
6 | 232222020151341 |
7 | 20350135154200 |
oct | 2732426604015 |
9 | 636134805027 |
10 | 201131231245 |
11 | 78332377a5a |
12 | 32b92538551 |
13 | 15c747b6389 |
14 | 9a4042d937 |
15 | 5372928d4a |
hex | 2ed45b080d |
201131231245 has 12 divisors (see below), whose sum is σ = 280762780284. Its totient is φ = 137918558400.
The previous prime is 201131231237. The next prime is 201131231293. The reversal of 201131231245 is 542132131102.
It can be written as a sum of positive squares in 2 ways, for example, as 102667694724 + 98463536521 = 320418^2 + 313789^2 .
It is not a de Polignac number, because 201131231245 - 23 = 201131231237 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 410471656 + ... + 410472145.
It is an arithmetic number, because the mean of its divisors is an integer number (23396898357).
Almost surely, 2201131231245 is an apocalyptic number.
It is an amenable number.
201131231245 is a deficient number, since it is larger than the sum of its proper divisors (79631549039).
201131231245 is an equidigital number, since it uses as much as digits as its factorization.
201131231245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 820943820 (or 820943813 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 201131231245 its reverse (542132131102), we get a palindrome (743263362347).
The spelling of 201131231245 in words is "two hundred one billion, one hundred thirty-one million, two hundred thirty-one thousand, two hundred forty-five".
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