Base | Representation |
---|---|
bin | 1011101101010010000… |
… | …1101100111010011001 |
3 | 201020011101021221101121 |
4 | 2323110201230322121 |
5 | 11243410312200441 |
6 | 232222201445241 |
7 | 20350201433233 |
oct | 2732441547231 |
9 | 636141257347 |
10 | 201134100121 |
11 | 78333a57429 |
12 | 32b934a0821 |
13 | 15c7527c136 |
14 | 9a40979253 |
15 | 5372ce3dd1 |
hex | 2ed486ce99 |
201134100121 has 2 divisors, whose sum is σ = 201134100122. Its totient is φ = 201134100120.
The previous prime is 201134100109. The next prime is 201134100131. The reversal of 201134100121 is 121001431102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 176127105625 + 25006994496 = 419675^2 + 158136^2 .
It is a cyclic number.
It is not a de Polignac number, because 201134100121 - 211 = 201134098073 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 201134100095 and 201134100104.
It is not a weakly prime, because it can be changed into another prime (201134100131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100567050060 + 100567050061.
It is an arithmetic number, because the mean of its divisors is an integer number (100567050061).
Almost surely, 2201134100121 is an apocalyptic number.
It is an amenable number.
201134100121 is a deficient number, since it is larger than the sum of its proper divisors (1).
201134100121 is an equidigital number, since it uses as much as digits as its factorization.
201134100121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 201134100121 its reverse (121001431102), we get a palindrome (322135531223).
The spelling of 201134100121 in words is "two hundred one billion, one hundred thirty-four million, one hundred thousand, one hundred twenty-one".
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