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201134100121 is a prime number
BaseRepresentation
bin1011101101010010000…
…1101100111010011001
3201020011101021221101121
42323110201230322121
511243410312200441
6232222201445241
720350201433233
oct2732441547231
9636141257347
10201134100121
1178333a57429
1232b934a0821
1315c7527c136
149a40979253
155372ce3dd1
hex2ed486ce99

201134100121 has 2 divisors, whose sum is σ = 201134100122. Its totient is φ = 201134100120.

The previous prime is 201134100109. The next prime is 201134100131. The reversal of 201134100121 is 121001431102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 176127105625 + 25006994496 = 419675^2 + 158136^2 .

It is a cyclic number.

It is not a de Polignac number, because 201134100121 - 211 = 201134098073 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201134100095 and 201134100104.

It is not a weakly prime, because it can be changed into another prime (201134100131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100567050060 + 100567050061.

It is an arithmetic number, because the mean of its divisors is an integer number (100567050061).

Almost surely, 2201134100121 is an apocalyptic number.

It is an amenable number.

201134100121 is a deficient number, since it is larger than the sum of its proper divisors (1).

201134100121 is an equidigital number, since it uses as much as digits as its factorization.

201134100121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 201134100121 its reverse (121001431102), we get a palindrome (322135531223).

The spelling of 201134100121 in words is "two hundred one billion, one hundred thirty-four million, one hundred thousand, one hundred twenty-one".