Base | Representation |
---|---|
bin | 10010101110110110… |
… | …100100100001000001 |
3 | 1220220201221002200022 |
4 | 102232312210201001 |
5 | 312143013110423 |
6 | 13123500103225 |
7 | 1311300110426 |
oct | 225666444101 |
9 | 56821832608 |
10 | 20113410113 |
11 | 859154a795 |
12 | 3a93b34b15 |
13 | 1b87035204 |
14 | d8b3a7d4d |
15 | 7cabbddc8 |
hex | 4aeda4841 |
20113410113 has 2 divisors, whose sum is σ = 20113410114. Its totient is φ = 20113410112.
The previous prime is 20113410101. The next prime is 20113410131. The reversal of 20113410113 is 31101431102.
Together with next prime (20113410131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19479226624 + 634183489 = 139568^2 + 25183^2 .
It is a cyclic number.
It is not a de Polignac number, because 20113410113 - 212 = 20113406017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20113410091 and 20113410100.
It is not a weakly prime, because it can be changed into another prime (20113410133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10056705056 + 10056705057.
It is an arithmetic number, because the mean of its divisors is an integer number (10056705057).
Almost surely, 220113410113 is an apocalyptic number.
It is an amenable number.
20113410113 is a deficient number, since it is larger than the sum of its proper divisors (1).
20113410113 is an equidigital number, since it uses as much as digits as its factorization.
20113410113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 20113410113 its reverse (31101431102), we get a palindrome (51214841215).
The spelling of 20113410113 in words is "twenty billion, one hundred thirteen million, four hundred ten thousand, one hundred thirteen".
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