Base | Representation |
---|---|
bin | 101101101110111000110001… |
… | …000010100000110111111011 |
3 | 222101011020101010102012121002 |
4 | 231232320301002200313323 |
5 | 202330340210122323303 |
6 | 1551435425431435215 |
7 | 60236314343502641 |
oct | 5556706102406773 |
9 | 871136333365532 |
10 | 201134141214203 |
11 | 590a656818294a |
12 | 1a685188b25b0b |
13 | 882cb39394842 |
14 | 3794d31529191 |
15 | 183be61ed5788 |
hex | b6ee310a0dfb |
201134141214203 has 2 divisors, whose sum is σ = 201134141214204. Its totient is φ = 201134141214202.
The previous prime is 201134141214197. The next prime is 201134141214211. The reversal of 201134141214203 is 302412141431102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201134141214203 - 238 = 200859263307259 is a prime.
It is not a weakly prime, because it can be changed into another prime (201134141214233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100567070607101 + 100567070607102.
It is an arithmetic number, because the mean of its divisors is an integer number (100567070607102).
Almost surely, 2201134141214203 is an apocalyptic number.
201134141214203 is a deficient number, since it is larger than the sum of its proper divisors (1).
201134141214203 is an equidigital number, since it uses as much as digits as its factorization.
201134141214203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 201134141214203 its reverse (302412141431102), we get a palindrome (503546282645305).
The spelling of 201134141214203 in words is "two hundred one trillion, one hundred thirty-four billion, one hundred forty-one million, two hundred fourteen thousand, two hundred three".
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