Base | Representation |
---|---|
bin | 10010101110110110… |
… | …101010001000110111 |
3 | 1220220201222021021021 |
4 | 102232312222020313 |
5 | 312143014330033 |
6 | 13123500402011 |
7 | 1311300234526 |
oct | 225666521067 |
9 | 56821867237 |
10 | 20113433143 |
11 | 8591566021 |
12 | 3a93b46307 |
13 | 1b8704283b |
14 | d8b3b24bd |
15 | 7cabc5b2d |
hex | 4aedaa237 |
20113433143 has 4 divisors (see below), whose sum is σ = 20114016048. Its totient is φ = 20112850240.
The previous prime is 20113433107. The next prime is 20113433257. The reversal of 20113433143 is 34133431102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20113433143 - 217 = 20113302071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20113443143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236203 + ... + 309868.
It is an arithmetic number, because the mean of its divisors is an integer number (5028504012).
Almost surely, 220113433143 is an apocalyptic number.
20113433143 is a deficient number, since it is larger than the sum of its proper divisors (582905).
20113433143 is an equidigital number, since it uses as much as digits as its factorization.
20113433143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 582904.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 20113433143 its reverse (34133431102), we get a palindrome (54246864245).
The spelling of 20113433143 in words is "twenty billion, one hundred thirteen million, four hundred thirty-three thousand, one hundred forty-three".
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