Base | Representation |
---|---|
bin | 1001001001011001001111… |
… | …11010010011000110110011 |
3 | 2122012212202100021202102212 |
4 | 10210230213322103012303 |
5 | 10114021433332104303 |
6 | 110440124504402335 |
7 | 4144121464210445 |
oct | 444544772230663 |
9 | 78185670252385 |
10 | 20114001441203 |
11 | 645533349614a |
12 | 230a28a4763ab |
13 | b2b9857b8317 |
14 | 4d7746a4c495 |
15 | 24d3283daad8 |
hex | 124b27e931b3 |
20114001441203 has 2 divisors, whose sum is σ = 20114001441204. Its totient is φ = 20114001441202.
The previous prime is 20114001441199. The next prime is 20114001441227. The reversal of 20114001441203 is 30214410041102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20114001441203 - 22 = 20114001441199 is a prime.
It is a super-2 number, since 2×201140014412032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20114001441263) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10057000720601 + 10057000720602.
It is an arithmetic number, because the mean of its divisors is an integer number (10057000720602).
Almost surely, 220114001441203 is an apocalyptic number.
20114001441203 is a deficient number, since it is larger than the sum of its proper divisors (1).
20114001441203 is an equidigital number, since it uses as much as digits as its factorization.
20114001441203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 20114001441203 its reverse (30214410041102), we get a palindrome (50328411482305).
The spelling of 20114001441203 in words is "twenty trillion, one hundred fourteen billion, one million, four hundred forty-one thousand, two hundred three".
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