Base | Representation |
---|---|
bin | 101101101110111111010010… |
… | …001110010011010011100111 |
3 | 222101011220102220121212012202 |
4 | 231232333102032103103213 |
5 | 202330444023420402211 |
6 | 1551442544140405115 |
7 | 60236652652564304 |
oct | 5556772216232347 |
9 | 871156386555182 |
10 | 201141140403431 |
11 | 590a952a023358 |
12 | 1a686600b4679b |
13 | 88306b3475727 |
14 | 37953d6d140ab |
15 | 183c2216de53b |
hex | b6efd23934e7 |
201141140403431 has 4 divisors (see below), whose sum is σ = 201571849483992. Its totient is φ = 200710431322872.
The previous prime is 201141140403421. The next prime is 201141140403443. The reversal of 201141140403431 is 134304041141102.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201141140403431 is a prime.
It is a super-2 number, since 2×2011411404034312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 201141140403394 and 201141140403403.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201141140403421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 215354539580 + ... + 215354540513.
It is an arithmetic number, because the mean of its divisors is an integer number (50392962370998).
Almost surely, 2201141140403431 is an apocalyptic number.
201141140403431 is a deficient number, since it is larger than the sum of its proper divisors (430709080561).
201141140403431 is an equidigital number, since it uses as much as digits as its factorization.
201141140403431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 430709080560.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 201141140403431 its reverse (134304041141102), we get a palindrome (335445181544533).
The spelling of 201141140403431 in words is "two hundred one trillion, one hundred forty-one billion, one hundred forty million, four hundred three thousand, four hundred thirty-one".
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