Base | Representation |
---|---|
bin | 1011101101010100000… |
… | …1000110011111001101 |
3 | 201020011221210010111121 |
4 | 2323111001012133031 |
5 | 11243414414100331 |
6 | 232223054120541 |
7 | 20350331415040 |
oct | 2732501063715 |
9 | 636157703447 |
10 | 201142331341 |
11 | 78338669696 |
12 | 32b961b0151 |
13 | 15c76ba1893 |
14 | 9a41abcc57 |
15 | 53738bcc11 |
hex | 2ed50467cd |
201142331341 has 4 divisors (see below), whose sum is σ = 229876950112. Its totient is φ = 172407712572.
The previous prime is 201142331321. The next prime is 201142331347. The reversal of 201142331341 is 143133241102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 201142331341 - 221 = 201140234189 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201142331347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14367309375 + ... + 14367309388.
It is an arithmetic number, because the mean of its divisors is an integer number (57469237528).
Almost surely, 2201142331341 is an apocalyptic number.
It is an amenable number.
201142331341 is a deficient number, since it is larger than the sum of its proper divisors (28734618771).
201142331341 is an equidigital number, since it uses as much as digits as its factorization.
201142331341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28734618770.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 201142331341 its reverse (143133241102), we get a palindrome (344275572443).
The spelling of 201142331341 in words is "two hundred one billion, one hundred forty-two million, three hundred thirty-one thousand, three hundred forty-one".
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