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201145303141 = 547367724503
BaseRepresentation
bin1011101101010100110…
…0011100000001100101
3201020012011101010001021
42323111030130001211
511243421144200031
6232223241531141
720350365603136
oct2732514340145
9636164333037
10201145303141
117833a309422
1232b971a3ab1
1315c776a2443
149a42253c8d
155373ca8511
hex2ed531c065

201145303141 has 4 divisors (see below), whose sum is σ = 201513028192. Its totient is φ = 200777578092.

The previous prime is 201145303109. The next prime is 201145303159. The reversal of 201145303141 is 141303541102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 201145303141 - 25 = 201145303109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201145313141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183861705 + ... + 183862798.

It is an arithmetic number, because the mean of its divisors is an integer number (50378257048).

Almost surely, 2201145303141 is an apocalyptic number.

It is an amenable number.

201145303141 is a deficient number, since it is larger than the sum of its proper divisors (367725051).

201145303141 is an equidigital number, since it uses as much as digits as its factorization.

201145303141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 367725050.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 201145303141 its reverse (141303541102), we get a palindrome (342448844243).

The spelling of 201145303141 in words is "two hundred one billion, one hundred forty-five million, three hundred three thousand, one hundred forty-one".

Divisors: 1 547 367724503 201145303141