Base | Representation |
---|---|
bin | 101101101111000011001010… |
… | …010110100000100011011101 |
3 | 222101012022012000212010210121 |
4 | 231233003022112200203131 |
5 | 202331031040121220123 |
6 | 1551444513210034541 |
7 | 60240161061631666 |
oct | 5557031226404335 |
9 | 871168160763717 |
10 | 201145303304413 |
11 | 59100275960496 |
12 | 1a687383118a51 |
13 | 8830bc7a62150 |
14 | 37956adb5036d |
15 | 183c3b6de175d |
hex | b6f0ca5a08dd |
201145303304413 has 4 divisors (see below), whose sum is σ = 216618018943228. Its totient is φ = 185672587665600.
The previous prime is 201145303304249. The next prime is 201145303304461. The reversal of 201145303304413 is 314403303541102.
201145303304413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 119844099812889 + 81301203491524 = 10947333^2 + 9016718^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201145303304413 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201145303304713) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7736357819388 + ... + 7736357819413.
It is an arithmetic number, because the mean of its divisors is an integer number (54154504735807).
Almost surely, 2201145303304413 is an apocalyptic number.
It is an amenable number.
201145303304413 is a deficient number, since it is larger than the sum of its proper divisors (15472715638815).
201145303304413 is a wasteful number, since it uses less digits than its factorization.
201145303304413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15472715638814.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 201145303304413 its reverse (314403303541102), we get a palindrome (515548606845515).
The spelling of 201145303304413 in words is "two hundred one trillion, one hundred forty-five billion, three hundred three million, three hundred four thousand, four hundred thirteen".
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