Base | Representation |
---|---|
bin | 1001001001011110010010… |
… | …01101101110011000001011 |
3 | 2122020010201221112012011101 |
4 | 10210233021031232120023 |
5 | 10114043004130243134 |
6 | 110441253220242231 |
7 | 4144245524556121 |
oct | 444571115563013 |
9 | 78203657465141 |
10 | 20116707665419 |
11 | 64564a2043492 |
12 | 230a904840377 |
13 | b2bcc7370b21 |
14 | 4d7922221911 |
15 | 24d435c9ee14 |
hex | 124bc936e60b |
20116707665419 has 2 divisors, whose sum is σ = 20116707665420. Its totient is φ = 20116707665418.
The previous prime is 20116707665381. The next prime is 20116707665449. The reversal of 20116707665419 is 91456670761102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20116707665419 - 213 = 20116707657227 is a prime.
It is a super-3 number, since 3×201167076654193 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 20116707665419.
It is not a weakly prime, because it can be changed into another prime (20116707665449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10058353832709 + 10058353832710.
It is an arithmetic number, because the mean of its divisors is an integer number (10058353832710).
Almost surely, 220116707665419 is an apocalyptic number.
20116707665419 is a deficient number, since it is larger than the sum of its proper divisors (1).
20116707665419 is an equidigital number, since it uses as much as digits as its factorization.
20116707665419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3810240, while the sum is 55.
The spelling of 20116707665419 in words is "twenty trillion, one hundred sixteen billion, seven hundred seven million, six hundred sixty-five thousand, four hundred nineteen".
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