Base | Representation |
---|---|
bin | 11101010001110100100… |
… | …011010010011010100011 |
3 | 21010100022202011012022012 |
4 | 131101310203102122203 |
5 | 230431034011231201 |
6 | 4140144452503135 |
7 | 265235144455232 |
oct | 35216443223243 |
9 | 7110282135265 |
10 | 2012000102051 |
11 | 7063146720a5 |
12 | 285b3291aaab |
13 | 117966733484 |
14 | 6d54a4d6b19 |
15 | 3750b76d5bb |
hex | 1d4748d26a3 |
2012000102051 has 2 divisors, whose sum is σ = 2012000102052. Its totient is φ = 2012000102050.
The previous prime is 2012000102017. The next prime is 2012000102083. The reversal of 2012000102051 is 1502010002102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2012000102051 - 26 = 2012000101987 is a prime.
It is not a weakly prime, because it can be changed into another prime (2012000102851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006000051025 + 1006000051026.
It is an arithmetic number, because the mean of its divisors is an integer number (1006000051026).
Almost surely, 22012000102051 is an apocalyptic number.
2012000102051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012000102051 is an equidigital number, since it uses as much as digits as its factorization.
2012000102051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 14.
Adding to 2012000102051 its reverse (1502010002102), we get a palindrome (3514010104153).
The spelling of 2012000102051 in words is "two trillion, twelve billion, one hundred two thousand, fifty-one".
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