Base | Representation |
---|---|
bin | 1001001001100100011011… |
… | …00101000100100100010001 |
3 | 2122020110020112121211011222 |
4 | 10210302031211010210101 |
5 | 10114121231020314303 |
6 | 110443000144014425 |
7 | 4144423260143621 |
oct | 444621545044421 |
9 | 78213215554158 |
10 | 20120002119953 |
11 | 645793273a98a |
12 | 230b484001415 |
13 | b2c400a60cc8 |
14 | 4d7b55996881 |
15 | 24d57a109938 |
hex | 124c8d944911 |
20120002119953 has 2 divisors, whose sum is σ = 20120002119954. Its totient is φ = 20120002119952.
The previous prime is 20120002119937. The next prime is 20120002120027. The reversal of 20120002119953 is 35991120002102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19579846207744 + 540155912209 = 4424912^2 + 734953^2 .
It is a cyclic number.
It is not a de Polignac number, because 20120002119953 - 24 = 20120002119937 is a prime.
It is not a weakly prime, because it can be changed into another prime (20120002119053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060001059976 + 10060001059977.
It is an arithmetic number, because the mean of its divisors is an integer number (10060001059977).
Almost surely, 220120002119953 is an apocalyptic number.
It is an amenable number.
20120002119953 is a deficient number, since it is larger than the sum of its proper divisors (1).
20120002119953 is an equidigital number, since it uses as much as digits as its factorization.
20120002119953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 35.
The spelling of 20120002119953 in words is "twenty trillion, one hundred twenty billion, two million, one hundred nineteen thousand, nine hundred fifty-three".
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