Base | Representation |
---|---|
bin | 11101010001110100101… |
… | …010111101001010010011 |
3 | 21010100022212221022122012 |
4 | 131101310222331022103 |
5 | 230431040020042042 |
6 | 4140145003533135 |
7 | 265235200526456 |
oct | 35216452751223 |
9 | 7110285838565 |
10 | 2012002112147 |
11 | 706315815335 |
12 | 285b3352a1ab |
13 | 117966c88391 |
14 | 6d54a89b49d |
15 | 3750ba18e82 |
hex | 1d474abd293 |
2012002112147 has 2 divisors, whose sum is σ = 2012002112148. Its totient is φ = 2012002112146.
The previous prime is 2012002112143. The next prime is 2012002112243. The reversal of 2012002112147 is 7412112002102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2012002112147 - 22 = 2012002112143 is a prime.
It is not a weakly prime, because it can be changed into another prime (2012002112143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006001056073 + 1006001056074.
It is an arithmetic number, because the mean of its divisors is an integer number (1006001056074).
Almost surely, 22012002112147 is an apocalyptic number.
2012002112147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012002112147 is an equidigital number, since it uses as much as digits as its factorization.
2012002112147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 448, while the sum is 23.
Adding to 2012002112147 its reverse (7412112002102), we get a palindrome (9424114114249).
The spelling of 2012002112147 in words is "two trillion, twelve billion, two million, one hundred twelve thousand, one hundred forty-seven".
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