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2012011120153 is a prime number
BaseRepresentation
bin11101010001110101001…
…101010100011000011001
321010100100111212222022001
4131101311031110120121
5230431044321321103
64140145525001001
7265235340225046
oct35216515243031
97110314788261
102012011120153
1170631a908171
12285b36553161
13117968ac0568
146d54bb641cd
153750c6e801d
hex1d475354619

2012011120153 has 2 divisors, whose sum is σ = 2012011120154. Its totient is φ = 2012011120152.

The previous prime is 2012011120099. The next prime is 2012011120157. The reversal of 2012011120153 is 3510211102102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1975284080704 + 36727039449 = 1405448^2 + 191643^2 .

It is a cyclic number.

It is not a de Polignac number, because 2012011120153 - 229 = 2011474249241 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2012011120153.

It is not a weakly prime, because it can be changed into another prime (2012011120157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006005560076 + 1006005560077.

It is an arithmetic number, because the mean of its divisors is an integer number (1006005560077).

Almost surely, 22012011120153 is an apocalyptic number.

It is an amenable number.

2012011120153 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012011120153 is an equidigital number, since it uses as much as digits as its factorization.

2012011120153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 2012011120153 its reverse (3510211102102), we get a palindrome (5522222222255).

The spelling of 2012011120153 in words is "two trillion, twelve billion, eleven million, one hundred twenty thousand, one hundred fifty-three".