Base | Representation |
---|---|
bin | 11101010001110101010… |
… | …001110101001100011011 |
3 | 21010100100121010002001001 |
4 | 131101311101311030123 |
5 | 230431100122200011 |
6 | 4140150010205431 |
7 | 265235353253005 |
oct | 35216521651433 |
9 | 7110317102031 |
10 | 2012012303131 |
11 | 706320545a36 |
12 | 285b36a23877 |
13 | 117969115b4c |
14 | 6d54bd91375 |
15 | 3750c87d7c1 |
hex | 1d47547531b |
2012012303131 has 2 divisors, whose sum is σ = 2012012303132. Its totient is φ = 2012012303130.
The previous prime is 2012012303089. The next prime is 2012012303143. The reversal of 2012012303131 is 1313032102102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2012012303131 - 27 = 2012012303003 is a prime.
It is a super-2 number, since 2×20120123031312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2012012303099 and 2012012303108.
It is not a weakly prime, because it can be changed into another prime (2012012303831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006006151565 + 1006006151566.
It is an arithmetic number, because the mean of its divisors is an integer number (1006006151566).
Almost surely, 22012012303131 is an apocalyptic number.
2012012303131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012012303131 is an equidigital number, since it uses as much as digits as its factorization.
2012012303131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 2012012303131 its reverse (1313032102102), we get a palindrome (3325044405233).
The spelling of 2012012303131 in words is "two trillion, twelve billion, twelve million, three hundred three thousand, one hundred thirty-one".
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