Base | Representation |
---|---|
bin | 101101101111110111111110… |
… | …011001100111101011010111 |
3 | 222101101201120002121010222020 |
4 | 231233313332121213223113 |
5 | 202332443204321010403 |
6 | 1551530532231104223 |
7 | 60244236254214363 |
oct | 5557677631475327 |
9 | 871351502533866 |
10 | 201202011110103 |
11 | 59122325a45203 |
12 | 1a69636a512073 |
13 | 8836364410b63 |
14 | 379832d29a2a3 |
15 | 183dad55d4453 |
hex | b6fdfe667ad7 |
201202011110103 has 16 divisors (see below), whose sum is σ = 278521892669280. Its totient is φ = 129041797723776.
The previous prime is 201202011110077. The next prime is 201202011110119. The reversal of 201202011110103 is 301011110202102.
It is not a de Polignac number, because 201202011110103 - 26 = 201202011110039 is a prime.
It is a super-2 number, since 2×2012020111101032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201202011110803) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4174464700 + ... + 4174512897.
It is an arithmetic number, because the mean of its divisors is an integer number (17407618291830).
Almost surely, 2201202011110103 is an apocalyptic number.
201202011110103 is a deficient number, since it is larger than the sum of its proper divisors (77319881559177).
201202011110103 is a wasteful number, since it uses less digits than its factorization.
201202011110103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8348977906.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 201202011110103 its reverse (301011110202102), we get a palindrome (502213121312205).
The spelling of 201202011110103 in words is "two hundred one trillion, two hundred two billion, eleven million, one hundred ten thousand, one hundred three".
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