Base | Representation |
---|---|
bin | 10010101111010000… |
… | …011110101100011111 |
3 | 1220221012201011102020 |
4 | 102233100132230133 |
5 | 312201232431030 |
6 | 13124301431223 |
7 | 1311411616044 |
oct | 225720365437 |
9 | 56835634366 |
10 | 20120202015 |
11 | 8595369631 |
12 | 3a9626b513 |
13 | 1b885727a4 |
14 | d8c2551cb |
15 | 7cb5b1510 |
hex | 4af41eb1f |
20120202015 has 16 divisors (see below), whose sum is σ = 34085989728. Its totient is φ = 10099552256.
The previous prime is 20120201999. The next prime is 20120202031. The reversal of 20120202015 is 51020202102.
It is an interprime number because it is at equal distance from previous prime (20120201999) and next prime (20120202031).
It is a cyclic number.
It is not a de Polignac number, because 20120202015 - 24 = 20120201999 is a prime.
It is a super-3 number, since 3×201202020153 (a number of 32 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a junction number, because it is equal to n+sod(n) for n = 20120201985 and 20120202003.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39451122 + ... + 39451631.
It is an arithmetic number, because the mean of its divisors is an integer number (2130374358).
Almost surely, 220120202015 is an apocalyptic number.
20120202015 is a deficient number, since it is larger than the sum of its proper divisors (13965787713).
20120202015 is a wasteful number, since it uses less digits than its factorization.
20120202015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78902778.
The product of its (nonzero) digits is 80, while the sum is 15.
Adding to 20120202015 its reverse (51020202102), we get a palindrome (71140404117).
The spelling of 20120202015 in words is "twenty billion, one hundred twenty million, two hundred two thousand, fifteen".
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